Figure 6.20 Competitive Inhibitor

The graph Figure 6.20 shows that

1. As the concentration of inhibitor ↑ es
   →the affinity for [s]↓s
2. But here V_max remains constant.

Note that as [S] → ∞, V_O → V_max, for any value of inhibitor concentration.

(However, the greater the concentration of I, the greater the [S] must be to approach V_max. Thus, I does not affect the turnover number of the enzyme. Rather, the presence of I has the effect of making [S] appear more dilute than it actually is, or attentively, making K_m appear larger than it really is.)

From these two points, we can make out that I is competitive inhibitors.

Note: We can determine K_m value from the hyperbolic curve but not K_i, so we have to find out with LB plot.