Consider the reaction
A → B
A mathematical relation for the free energy change can be derived.
ΔG = ΔG° + RT ln ![]()
Where
ΔG° = Standard free energy change
R = Gas constant
T = Absolute temperature
ln = Natural logarithm
B = Concentration of product
A = Concentration of reactant
ΔG° is related to equilibrium constant (Keq)
When a reaction A ↔ B is at equilibrium (eq), the free energy change is zero. The above equation may be written as,
ΔG = 0 = ΔG° + RT In ![]()
Hence ΔG° = −RT ln Keq.
When ΔG° is negative (the products contain less free energy than the reactants), the reaction will proceed to form the products under standard conditions.
When ΔG° is positive (the products of the reaction contain more free energy than the reactants), the reaction will tend to go in the reverse direction.
Relationship among K′eq and ΔG° and direction of the chemical reaction:
| When K′eq is | ΔG° is | Starting with 1M concentration of substrate |
|---|---|---|
| > 1.0 | negative | proceeds forward |
| 1 | zero | remains at equilibrium |
| < 1.0 | positive | proceeds backward |
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